Question

生理鹽水是O.9%的NaCl溶液，欲配制1000g此溶液，需要NaCl    g，水    g．

Answer 1

【答案】分析：利用一定量溶液中溶質(zhì)質(zhì)量=溶液質(zhì)量×溶液中溶質(zhì)的質(zhì)量分?jǐn)?shù)，可根據(jù)溶液的質(zhì)量和溶液的質(zhì)量分?jǐn)?shù)計(jì)算配制溶液所需要的溶質(zhì)的質(zhì)量；再根據(jù)溶劑質(zhì)量=溶液質(zhì)量-溶質(zhì)質(zhì)量即可求得所需水的質(zhì)量．
解答：解：根據(jù)溶質(zhì)質(zhì)量=溶液質(zhì)量×溶液中溶質(zhì)的質(zhì)量分?jǐn)?shù)可得：
氯化鈉溶質(zhì)的質(zhì)量=1000g×0.9%=9g；
則再根據(jù)溶劑質(zhì)量=溶液質(zhì)量-溶質(zhì)質(zhì)量可得：
水的質(zhì)量=1000g-9g=991g．
故答案為：9，991．
點(diǎn)評(píng)：本題考查了有關(guān)溶質(zhì)質(zhì)量分?jǐn)?shù)的有關(guān)計(jì)算，完成此題，可以依據(jù)溶質(zhì)質(zhì)量分?jǐn)?shù)計(jì)算公式進(jìn)行．