解答:解:(1)設(shè)碳酸鈉與氯化鈣反應(yīng)生成沉淀的質(zhì)量為x,生成NaCl的質(zhì)量為y. 氯化鈣消耗的碳酸鈉的質(zhì)量為(200g-100g)×10.6%=10.6g, Na2CO3+CaCl2═CaCO3↓+2NaCl 106 l00 117 l0.6 g x y
106
10.6g
=
100
x
x=10g
106
10.6g
=
117
y
y=11.7g 故答案為:10; (2)設(shè)碳酸鈉與鹽酸反應(yīng)生成NaCl的質(zhì)量為z. Na2CO3+2HCl=2NaCl+CO2↑+H2O 106 117 100g×10.6% z
106
100g×10.6%
=
117
z
z=11.7 g 反應(yīng)后溶液中溶質(zhì)的質(zhì)量為ll.7+11.7=23.4 g 答:當(dāng)加入200g 10.6%的Na2CO3溶液時,所得溶液中溶質(zhì)的質(zhì)量為23.4g.