分析:掌握解一元一次方程的步驟:去分母,去括號(hào),移項(xiàng),合并同類項(xiàng),化系數(shù)為1.
解答:解:(1)整理,得2t-3t=5+4,-t=9,
解得t=-9;
(2)整理,得7-4x=12+12x-21,
移項(xiàng)得,-4x-12x=12-21-7,
合并同類項(xiàng)得,-16x=-16,
解得x=1;
(3)整理,得5x-10=4-4+x,
移項(xiàng)得,5x-x=10,
合并同類項(xiàng)得,4x=10,
解得x=
;
(4)整理,得4(1-y)-12y=36-3(y+2),
去括號(hào)得,4-4y-12y=36-3y-6,
移項(xiàng)合并同類項(xiàng)得,-13y=26,
解得y=-2;
(5)整理,得1.5x-1-5x=1.5,
合并同類項(xiàng)得,-3.5x=2.5,
解得x=-
.
點(diǎn)評(píng):去分母時(shí),方程兩端同乘各分母的最小公倍數(shù)時(shí),不要漏乘沒有分母的項(xiàng),同時(shí)要把分子(如果是一個(gè)多項(xiàng)式)作為一個(gè)整體加上括號(hào).