Question

多項(xiàng)式2b+

1

4

ab²-5ab-1的次數(shù)是

 

，二次項(xiàng)的系數(shù)是

 

．

Answer 1

分析：根據(jù)多項(xiàng)式的有關(guān)概念進(jìn)行解答．多項(xiàng)式的次數(shù)是多項(xiàng)式中最高次項(xiàng)的次數(shù)．因?yàn)槎�次�?xiàng)為-5ab，所以系數(shù)為-5．

解答：解：此多項(xiàng)式中共含有四個(gè)單項(xiàng)式，其中

1

4

ab2未知數(shù)的次數(shù)總和最大為3即為此多項(xiàng)式的次數(shù)，二次項(xiàng)為-5ab，其系數(shù)為-5．

點(diǎn)評(píng)：本題重點(diǎn)為多項(xiàng)式的項(xiàng)數(shù)，次數(shù)和系數(shù)的求解．多項(xiàng)式中含有單項(xiàng)式的個(gè)數(shù)即為多項(xiàng)式的項(xiàng)數(shù)，包含的單項(xiàng)式中未知數(shù)的次數(shù)總和的最大值即為多項(xiàng)式的次數(shù)．