Question

如圖，△ABC≌△EFC，CF=3cm，CE=4cm，∠F=36°，則BC=　 　cm，∠B=　   　度．

Answer 1

3   36

試題分析：運(yùn)用“全等三角形的對(duì)應(yīng)邊相等，對(duì)應(yīng)角相等”即可得，做題時(shí)要根據(jù)△ABC≌△EFC找對(duì)對(duì)應(yīng)邊．
解：∵△ABC≌△EFC，CF=3cm，∠F=36，
∴BC的對(duì)應(yīng)邊是CF，∠B的對(duì)應(yīng)角是∠F，
∴BC=FC=3cm，∠B=∠F=36°．
故填3，36．
點(diǎn)評(píng)：本題考查了全等三角形的性質(zhì)及對(duì)應(yīng)關(guān)系的找法；全等三角形書寫時(shí)各對(duì)應(yīng)頂點(diǎn)應(yīng)在同一位置，找準(zhǔn)對(duì)應(yīng)關(guān)系是解決本題的關(guān)鍵．