Question

計(jì)算 (-

1

2

)-1-3tan30°+(1-

2

)0+

12

=

3

-1

．

Answer 1

分析：分別根據(jù)負(fù)整數(shù)指數(shù)冪、特殊角的三角函數(shù)值、0指數(shù)冪的計(jì)算法則計(jì)算出各數(shù)，再根據(jù)實(shí)數(shù)混合運(yùn)算的法則進(jìn)行計(jì)算即可．

解答：解：原式=-2-3×

3

3

+1+2

3

=-2-

3

+1+2

3

=

3

-1．

點(diǎn)評(píng)：本題考查的是實(shí)數(shù)的運(yùn)算，熟知負(fù)整數(shù)指數(shù)冪、0指數(shù)冪的計(jì)算法則，熟記特殊角的三角函數(shù)值是解答此題的關(guān)鍵．