計(jì)算: (15axn+2-9a2x2n+6a3x3n)÷3axn

答案:
解析:

解: (15axn+2-9a2x2n+6a3x3n)÷3axn

=15axn+2÷3axn+(-9a2x2n)÷3axn+6a3x3n÷3axn

=5x2-3axn+2a2x2n;


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