(2002•呼和浩特)計(jì)算下列各式,結(jié)果為-9a6b-4的是( )
A.(-3a3b-2)2
B.-(3a4b-2)2
C.-(3a4b-6)2
D.-(3a3b-2)2
【答案】分析:根據(jù)積的乘方,等于把每一個(gè)因式分別乘方,再把所得的冪相乘,對(duì)各選項(xiàng)計(jì)算后利用排除法求解.
解答:解:A、應(yīng)為(-3a3b-2)2=9a6b-4,故本選項(xiàng)錯(cuò)誤;
B、應(yīng)為-(3a4b-2)2=-9a8b-4,故本選項(xiàng)錯(cuò)誤;
C、應(yīng)為-(3a4b-6)2=-9a8b-12,故本選項(xiàng)錯(cuò)誤;
D、-(3a3b-2)2=-9a6b-4,正確.
故選D.
點(diǎn)評(píng):本題主要考查積的乘方的性質(zhì),熟練掌握性質(zhì)是解題的關(guān)鍵.