Question

【題目】如果△ABC和△DEF這兩個(gè)三角形全等，點(diǎn)C和點(diǎn)E，點(diǎn)B和點(diǎn)Ｄ分別是對(duì)應(yīng)點(diǎn)，則另一組對(duì)應(yīng)點(diǎn)是________，對(duì)應(yīng)邊是______________，對(duì)應(yīng)角是_____________，表示這兩個(gè)三角形全等的式子是___________.

Answer 1

【答案】點(diǎn)A與點(diǎn)F,AB與FD，BC與DE，AC與FE,∠A=∠F，∠C=∠E，∠B=∠D,△ABC≌△FDE

【解析】

利用全等三角形的性質(zhì)得出對(duì)應(yīng)邊以及對(duì)應(yīng)角即可．

如圖所示：∵△ABC和△DEF這兩個(gè)三角形全等,點(diǎn)C和點(diǎn)E,點(diǎn)B和點(diǎn)D分別是對(duì)應(yīng)點(diǎn),

∴則另一組對(duì)應(yīng)點(diǎn)是點(diǎn)A和點(diǎn)F,對(duì)應(yīng)邊是AB與FD，BC與DE，AC與FE, (只需填寫一組)對(duì)應(yīng)角是∠A=∠F, ∠C=∠E，∠B=∠D,

△ABC≌△DEF，

故答案為：點(diǎn)A和點(diǎn)F; AB與FD，BC與DE，AC與FE; ∠A=∠F, ∠C=∠E，∠B=∠D. △ABC≌△FDE.