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第四單元  三角函數(shù)的圖象和性質(zhì)

一.選擇題

(1)下列函數(shù)中,最小正周期為6ec8aac122bd4f6e的是                                                                           (      )

A.6ec8aac122bd4f6e          B.6ec8aac122bd4f6e  

C.6ec8aac122bd4f6e         D.6ec8aac122bd4f6e

(2)將函數(shù)6ec8aac122bd4f6e的圖象向左平移6ec8aac122bd4f6e個(gè)單位,得到6ec8aac122bd4f6e的圖象,則6ec8aac122bd4f6e等于                                                                                                                                       (      )

A.6ec8aac122bd4f6e              B.6ec8aac122bd4f6e        C.6ec8aac122bd4f6e                  D.6ec8aac122bd4f6e

(3)下列命題中正確的是                                                                                                    (      )

    A.6ec8aac122bd4f6e為增函數(shù)                 B.6ec8aac122bd4f6e在第一象限為增函數(shù)

    C.6ec8aac122bd4f6e為奇函數(shù)             D.6ec8aac122bd4f6e的反函數(shù)為6ec8aac122bd4f6e

(4)6ec8aac122bd4f6e單調(diào)增區(qū)間為                                                                               (      )

    A.6ec8aac122bd4f6e                    B.6ec8aac122bd4f6e

C.6ec8aac122bd4f6e                  D.6ec8aac122bd4f6e

(5)函數(shù)y = - xcosx的部分圖象是                                                                                       (      )

6ec8aac122bd4f6e

 (6)6ec8aac122bd4f6e(A>0,ω>0)在x=1處取最大值,則                        (      )

    A.6ec8aac122bd4f6e一定是奇函數(shù)     B.6ec8aac122bd4f6e一定是偶函數(shù)

    C.6ec8aac122bd4f6e一定是奇函數(shù)     D.6ec8aac122bd4f6e一定是偶函數(shù)

(7)已知6ec8aac122bd4f6e為奇函數(shù),則6ec8aac122bd4f6e的一個(gè)取值                        (      )

    A.0                   B.π               C.6ec8aac122bd4f6e      D.6ec8aac122bd4f6e

(8)6ec8aac122bd4f6e的圖象中相鄰的兩條對(duì)稱軸間距離為                           (      )

    A.3π                     B.6ec8aac122bd4f6e          C.6ec8aac122bd4f6e        D.6ec8aac122bd4f6e

(9)函數(shù)6ec8aac122bd4f6e的一條對(duì)稱軸方程(      )

    A.6ec8aac122bd4f6e          B.6ec8aac122bd4f6e              C.6ec8aac122bd4f6e          D.6ec8aac122bd4f6e6ec8aac122bd4f6e

(10)使6ec8aac122bd4f6e(ω>0)在區(qū)間[0,1]至少出現(xiàn)2次最大值,則ω的最小值為(      )

A.6ec8aac122bd4f6e            B.6ec8aac122bd4f6e C.π                   D.6ec8aac122bd4f6e

二.填空題

(11)把函數(shù)y = cos(x+6ec8aac122bd4f6e)的圖象向左平移m個(gè)單位(m>0), 所得圖象關(guān)于y軸對(duì)稱, 則m的最小值是_________。

(12)函數(shù)y = -2sin(4x+6ec8aac122bd4f6e)的圖象與x軸的交點(diǎn)中, 離原點(diǎn)最近的一點(diǎn)的坐標(biāo)是_______。

(13)6ec8aac122bd4f6e的圖象關(guān)于6ec8aac122bd4f6e對(duì)稱,則a等于___________。

(14)①存在6ec8aac122bd4f6e使6ec8aac122bd4f6e

②存在區(qū)間(a,b)使6ec8aac122bd4f6e為減函數(shù)而6ec8aac122bd4f6e<0

6ec8aac122bd4f6e在其定義域內(nèi)為增函數(shù)

6ec8aac122bd4f6e既有最大、最小值,又是偶函數(shù)

6ec8aac122bd4f6e最小正周期為π

以上命題錯(cuò)誤的為____________。

三解答題:

15.函數(shù)6ec8aac122bd4f6e最小正周期為π,最大值為3,且6ec8aac122bd4f6e≠0),求f (x)的的解析式。

16.求6ec8aac122bd4f6e的最小正周期、最大值、最小值

 

 

 

 

 

 

 

17.P為直徑AB=4的半圓上一點(diǎn),C為AB延長(zhǎng)線上一點(diǎn),BC=2,△PCQ為正△,問

∠POC為多大時(shí),四邊形OCQP面積最大,最大面積為多少?

 

 

 

 

 

 

 

 

 

 

18.6ec8aac122bd4f6e(ω>0)

(1)若f (x +θ)是周期為2π的偶函數(shù),求ω及θ值

(2)f (x)在(0,6ec8aac122bd4f6e)上是增函數(shù),求ω最大值。

 

 

 

 

 

 

 

 

 

 

 

 

答案

一選擇題:

1.       B 

[解析]:正弦、余弦型最小正周期為T=6ec8aac122bd4f6e,正切型最小正周期為T=6ec8aac122bd4f6e

2.C 

[解析]:函數(shù)6ec8aac122bd4f6e的圖象向左平移6ec8aac122bd4f6e個(gè)單位,得到6ec8aac122bd4f6e的圖象,故6ec8aac122bd4f6e

3.C 

[解析]:A、B、D都是定義域的問題

6ec8aac122bd4f6e,故選C

4.B 

[解析]:∵6ec8aac122bd4f6e=6ec8aac122bd4f6e

∴要求單調(diào)增區(qū)間就是解6ec8aac122bd4f6e

6ec8aac122bd4f6e        6ec8aac122bd4f6e

5.D  

[解析]:∵函數(shù)y = - xcosx是奇函數(shù),∴排除A、C,

又當(dāng)x取一個(gè)小正數(shù)時(shí),y的值為負(fù),故選D

6.D 

[解析]: ∵6ec8aac122bd4f6e(A>0,ω>0)在x=1處取最大值

6ec8aac122bd4f6ex=0處取最大值, 即y軸是函數(shù)6ec8aac122bd4f6e的對(duì)稱軸

∴函數(shù)6ec8aac122bd4f6e是偶函數(shù)

7.D 

[解析]:∵6ec8aac122bd4f6e為奇函數(shù)

               而6ec8aac122bd4f6e=6ec8aac122bd4f6e

            ∴6ec8aac122bd4f6e的一個(gè)取值為6ec8aac122bd4f6e

 

8.C 

[解析]:  ∵6ec8aac122bd4f6e=6ec8aac122bd4f6e

∴圖象的對(duì)稱軸為6ec8aac122bd4f6e,即6ec8aac122bd4f6e

故相鄰的兩條對(duì)稱軸間距離為6ec8aac122bd4f6e

9.A 

[解析]:當(dāng)6ec8aac122bd4f6e時(shí) 6ec8aac122bd4f6e  取得最小值-1,故選A

10.A

[解析]:要使6ec8aac122bd4f6e(ω>0)在區(qū)間[0,1]至少出現(xiàn)2次最大值

             只需要最小正周期6ec8aac122bd4f6e6ec8aac122bd4f6e6ec8aac122bd4f6e1,故6ec8aac122bd4f6e

二填空題:

11.6ec8aac122bd4f6eπ

[解析]:把函數(shù)y = cos(x+6ec8aac122bd4f6e)的圖象向左平移m個(gè)單位(m>0),

得到圖象y = cos(x+6ec8aac122bd4f6e+m),而此圖象關(guān)于y軸對(duì)稱

故m的最小值是6ec8aac122bd4f6eπ   

12.. (6ec8aac122bd4f6e, 0)

[解析]:∵函數(shù)y = -2sin(4x+6ec8aac122bd4f6e)的圖象與x軸的相交

              ∴4x+6ec8aac122bd4f6e=6ec8aac122bd4f6e, ∴6ec8aac122bd4f6e  

              當(dāng)k=1時(shí),交點(diǎn)離原點(diǎn)最近,坐標(biāo)為(6ec8aac122bd4f6e, 0)。

13.-1

[解析]:6ec8aac122bd4f6e的圖象關(guān)于6ec8aac122bd4f6e對(duì)稱,

6ec8aac122bd4f6e    即a  =6ec8aac122bd4f6e    

14.①②③⑤

[解析]:①當(dāng)6ec8aac122bd4f6e時(shí)6ec8aac122bd4f6e,故①錯(cuò)

②若6ec8aac122bd4f6e為減函數(shù)則6ec8aac122bd4f6e,此時(shí)6ec8aac122bd4f6e>0,故②錯(cuò)

③當(dāng)x分別去6ec8aac122bd4f6e時(shí),y都是0,故③錯(cuò)

④∵6ec8aac122bd4f6e=6ec8aac122bd4f6e

∴既有最大、最小值,又是偶函數(shù),故④對(duì)

6ec8aac122bd4f6e最小正周期為6ec8aac122bd4f6e,故⑤錯(cuò)

三解答題:

15.解:6ec8aac122bd4f6e=6ec8aac122bd4f6e

               又最小正周期為π,最大值為3,且6ec8aac122bd4f6e≠0),

6ec8aac122bd4f6e,6ec8aac122bd4f6e

6ec8aac122bd4f6e+1=3,6ec8aac122bd4f6e

解得6ec8aac122bd4f6e

因此6ec8aac122bd4f6e

16.解:

6ec8aac122bd4f6e

故最小正周期、最大值、最小值分別為6ec8aac122bd4f6e

 

 

17.解:設(shè)∠POC=6ec8aac122bd4f6e,在ΔOPC中由余弦定理得PC2=20-16cos6ec8aac122bd4f6e

S6ec8aac122bd4f6e=4sin6ec8aac122bd4f6e,6ec8aac122bd4f6e

6ec8aac122bd4f6e

故當(dāng)6ec8aac122bd4f6e=6ec8aac122bd4f6e時(shí),四邊形OCQP面積最大,最大面積為6ec8aac122bd4f6e

18.解:

(1)       因?yàn)?i>f (x +θ)=6ec8aac122bd4f6e

f (x +θ)是周期為2π的偶函數(shù),

6ec8aac122bd4f6e Z

(2)因?yàn)?i>f (x)在(0,6ec8aac122bd4f6e)上是增函數(shù),故ω最大值為6ec8aac122bd4f6e

 

 

 

本資料來源于《七彩教育網(wǎng)》http://www.7caiedu.cn


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