1.如圖所示.一列簡(jiǎn)諧橫波沿x軸正方向傳播.從波傳到x=5m的M點(diǎn)時(shí)開(kāi)始計(jì)時(shí).已知P點(diǎn)相繼出現(xiàn)兩個(gè)波峰的時(shí)間間隔為0.4s.下面說(shuō)法中正確的是 學(xué)科網(wǎng) 查看更多

 

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如圖所示,一列簡(jiǎn)諧橫波沿x軸正方向傳播,實(shí)線為t1=0時(shí)的波形圖,虛線為t2=0.06s時(shí)的波形圖,則t2=0.06s時(shí)P質(zhì)點(diǎn)向y軸
負(fù)
負(fù)
(選填“正”或“負(fù)”)方向運(yùn)動(dòng).已知周期 T>0.06s,則該波的傳播速度為
15
15
m/s.

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如圖所示,一列簡(jiǎn)諧橫波沿x軸正方向傳播,從波傳到x=5m的M點(diǎn)時(shí)開(kāi)始計(jì)時(shí),已知P點(diǎn)相繼出現(xiàn)兩個(gè)波峰的時(shí)間間隔為0.4s,下面說(shuō)法中正確的是(  )

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如圖所示,一列簡(jiǎn)諧橫波沿x軸正方向傳播,從波傳到x=5m處的M點(diǎn)開(kāi)始計(jì)時(shí)(t=0s),已知開(kāi)始計(jì)時(shí)后,P點(diǎn)(x=1m)在t=0.3s的時(shí)刻第一次到達(dá)波峰,下面說(shuō)法中正確的是(  )

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如圖所示,一列簡(jiǎn)諧橫波沿x軸正方向傳播.t=0時(shí),波傳播到x軸上的質(zhì)點(diǎn)B,在它的左邊質(zhì)點(diǎn)A位于正的最大位移處,在t=0.6s時(shí),質(zhì)點(diǎn)A第二次出現(xiàn)在負(fù)的最大位移處.求:
(1)該波的周期T
(2)該波的波速v
(3)從t=0時(shí)開(kāi)始到質(zhì)點(diǎn)E第一次到達(dá)正向最大位移經(jīng)歷的時(shí)間及在該段時(shí)間內(nèi)質(zhì)點(diǎn)E通過(guò)的路程.

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如圖所示,一列簡(jiǎn)諧橫波沿x軸正方向傳播,實(shí)線表示t=0時(shí)刻的波形,虛線表示t=0.7s時(shí)刻的波形.則關(guān)于這列波說(shuō)法錯(cuò)誤的是( 。

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一、本題共10小題,每小題5分.每小題給出的四個(gè)選項(xiàng)中,有的小題只有一個(gè)選項(xiàng)正確,有的小題有多個(gè)選項(xiàng)正確,全部選對(duì)得5分,選不全得3分,有選錯(cuò)或不答得0分.

題號(hào)

1

2

3

4

5

6

7

8

9

10

答案

AB

D

B

D

AC

C

A

D

B

BCD

學(xué)科網(wǎng)(Zxxk.Com)二、本題共2小題,共18分

  11(4分)偏小

12.(8分)(1)電路圖(4分)

 

 

(2)9.0,10.0 (每空2分)

 

13.(4分)右  (2分)          t=  (2分)

14、(13分)解:(1)飛船在運(yùn)行過(guò)程中萬(wàn)有引力提供向心力

 

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2分)

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

由(2) (3)得:飛船運(yùn)行周期:

2分)

 

 

 

 

 

 

 

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15.(13分)解(1)如圖所示,帶電質(zhì)點(diǎn)在重力mg(大小及方向均已知)、洛倫茲力qv0B(方向已知)、電場(chǎng)力qE(大小及方向均未知)的作用做勻速直線運(yùn)動(dòng)。根據(jù)力三角形知識(shí)分析可知:當(dāng)電場(chǎng)力方向與磁場(chǎng)方向相同時(shí),場(chǎng)強(qiáng)有最小值。

學(xué)科網(wǎng)(Zxxk.Com)根據(jù)物體的平衡規(guī)律有

                     (1分)

                     (1分)

解得                     (2分)

                          (2分)

(2)當(dāng)電場(chǎng)力和重力平衡時(shí),帶點(diǎn)質(zhì)點(diǎn)才能只受洛倫茲力作用做勻速圓周運(yùn)動(dòng)

則有:                 (1分)

得:                   (1分)

要使帶電質(zhì)點(diǎn)經(jīng)過(guò)x軸,圓周的直徑為   (2分)

根據(jù)(1分)

                           (2分)

16.(12分)解:⑴小球做勻速圓周運(yùn)動(dòng),突然放繩則小球以原有的速度做勻速直線運(yùn)動(dòng)到C,在C點(diǎn)處一瞬間8m繩突然拉直,沿繩方向的速度vyP突變?yōu)?,而小球?qū)⒁詖x做勻速圓周運(yùn)動(dòng),到達(dá)B點(diǎn),

學(xué)科網(wǎng)(Zxxk.Com)由幾何關(guān)系可知:S1=AC=   (1分)

∠AOC=60°=π/3

     (2分)                      

∠BOC=120°=2π/3     (1分)

在C點(diǎn),由矢量三角形可知:vx=vcos60°=v/2    (1分)

    (2分)

 (2分)

學(xué)科網(wǎng)(Zxxk.Com)(2)在B點(diǎn),則有:    (3分)

    解:(1)小物塊沿斜面下滑的過(guò)程中受力情況如圖所示

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