根據(jù)短文內(nèi)容，從短文后的選項(xiàng)中選出能填入空白處的最佳選項(xiàng)。選項(xiàng)中有兩項(xiàng)為多余選項(xiàng)。
A group of happy, high-performing individuals is not a team. Even if each of the people is highly motivated and wants to do great work, you will still need to spend time actively developing a sense of unity and cooperation to create a truly team-oriented(團(tuán)隊(duì)精神的)environment. 【小題1】
Building a team takes time. 【小題2】 We will review the building blocks of a team environment, so you can work on this aspect of your role over time.
Successful teams have some common attributes（品質(zhì)） you can encourage and develop as you work with the members of your group.【小題3】Making them clear to every member of your group is a great first step toward developing a team-oriented culture.
All effective teams operate on the basis of trust. 【小題4】Each member on your team needs to see consistent(一致的)behavior patterns from you and their colleagues over time to be able to believe a certain person will act in a certain way.
【小題5】  While having these discussions can be great for your team’s creativity, you want to ensure they remain within respectful communication. Challenging another team member’s view can help refine an idea and make it more perfect. You should encourage everyone to contribute to the discussion.
A．Building a great team needs a lot of skills.
B．A healthy team will have debates, and sometimes even heated discussions.
C．Your aim is to encourage your team members to work together.
D．You can’t expect to achieve success quickly.
E. You will need to show these values through your actions as well as your words.
F. Therefore, working with others is not the same as being mutually（相互地） supportive and dependent on one another.
G. Trust is based on pattern recognition.

【小題1】F
【小題1】D
【小題1】E
【小題1】G
【小題1】B解析:
略
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科目：初中物理 來(lái)源： 題型：閱讀理解

（2013?南通模擬）閱讀短文，回答問(wèn)題：
如圖甲是一種可調(diào)溫蒸汽電熨斗，其說(shuō)明書(shū)的部分內(nèi)容如下：
產(chǎn)品特點(diǎn)：具有干濕兩用功能．干用功能是指在無(wú)水狀態(tài)下，通過(guò)電加熱管加熱底板，底板溫度上升，直接壓燙衣物；濕用功能是指在蒸汽狀態(tài)下熨燙．自動(dòng)恒溫設(shè)置．針對(duì)不同面料可調(diào)節(jié)底板溫度．
技術(shù)參數(shù)：自身質(zhì)量：1.3kg   額定功率：1000W  額定電壓：220V
在額定電壓下工作時(shí)能達(dá)到的最大噴氣量：15g/min
（1）某師傅在用熨斗干燙衣服時(shí)，用了19N向下的力壓熨斗，如果熨斗底板與衣服接觸的面積為160cm2，在此過(guò)程中，衣服受到的壓強(qiáng)為
2000
2000
Pa．（g取10N/kg）
（2）用熨斗汽燙前先預(yù)熱，使金屬底板的溫度從20℃升高到220℃，溫控開(kāi)關(guān)自動(dòng)斷開(kāi)．已知金屬底板的質(zhì)量為1kg，金屬底板的比熱容為0.46×103J/（kg?℃）．則蒸汽電熨斗預(yù)熱過(guò)程中金屬底板吸收的熱量為
9.2×104
9.2×104
J．
（3）設(shè)計(jì)生產(chǎn)電熨斗時(shí)，技術(shù)人員會(huì)根據(jù)不同部分的作用選用具有不同物理屬性的材料．“水位觀察窗”選用的材料應(yīng)具有很好的
透明度
透明度
 （選填“硬度”、“延展性”或“透明度”）；用熨斗汽燙時(shí)，可以看到熨斗底板蒸汽口的周?chē)写罅俊鞍嘴F”，這是因?yàn)樗?!--BA-->
汽化
汽化
后
液化
液化
上兩格均填物態(tài)變化名稱(chēng)）形成的小水珠；某次使用時(shí)發(fā)現(xiàn)從蒸汽口噴出的是水柱而不是“白霧”，請(qǐng)你猜想可能的原因是
水的溫度未達(dá)到沸點(diǎn)，沒(méi)有沸騰
水的溫度未達(dá)到沸點(diǎn)，沒(méi)有沸騰
．
（4）若某次使用中，該電熨斗（額定電壓下）在最大噴氣量狀態(tài)下工作時(shí)消耗的電能中只有70%被水吸收，則該狀態(tài)下每克水噴出前吸收的熱量是
2800
2800
J．
（5）如圖乙所示為自動(dòng)調(diào)溫電熨斗的電路圖．右下方為溫控部分，A為雙金屬片，由兩層不同金屬粘合而成，受熱時(shí)二者膨脹的快慢不同．在未通電和低于預(yù)定溫度時(shí)，雙金屬片A和靜片B上的觸點(diǎn)接通，指示燈L亮，電熱絲R發(fā)熱，當(dāng)溫度達(dá)到預(yù)定溫度時(shí)，由于雙金屬片的金屬層
b
b
（填“a”或“b”）膨脹較快，向左彎曲，電路斷開(kāi)，如圖丙所示．調(diào)節(jié)調(diào)溫旋鈕C，使靜片向左時(shí)，調(diào)溫電熨斗的預(yù)定溫度值將變
高
高
（選填“高”、“低”）．
（6）近年來(lái)用一種主要成分為BaTiO3被稱(chēng)為“PTC”的特殊材料作為發(fā)熱體，既可省電，又能自動(dòng)調(diào)溫，避免了老產(chǎn)品采用雙金屬片制成的調(diào)溫器溫控質(zhì)量不可靠的問(wèn)題．如圖丁是“PTC”材料的電阻隨溫度變化的關(guān)系圖象．當(dāng)發(fā)熱體產(chǎn)生的熱與向外散發(fā)的熱平衡時(shí)，溫度達(dá)到一個(gè)穩(wěn)定值．由圖象可以判定：通電后，PTC電熨斗的功率變化情況是
先變大后變小
先變大后變小
，穩(wěn)定時(shí)的溫度應(yīng)取
T1-T2
T1-T2
區(qū)間的某一值．

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科目：初中物理 來(lái)源： 題型：閱讀理解


第二節(jié) （共5小題；每小題2分，滿分10分）
根據(jù)短文內(nèi)容，從短文后的選項(xiàng)中選出能填入空白處的最佳選項(xiàng)。選項(xiàng)中有兩項(xiàng)為多余選項(xiàng)。
Why do some people have many friends while others do not? ___71___ However, it is not so. Let’s look at two psychological experiments which will give you the key to happy interpersonal relations.
The first experiment is called the “Hawthorne effect” after Hawthorne, Illinois(伊利諾斯[美國(guó)州名]), where the experiment took place. A group of psychologists examined the work patterns of two groups of workers in the Western Electric Company. ____72_____. The psychologists changed the working conditions for one group twice but left the other group alone. They were surprised to find that productivity increased on both occasions and in both groups. They concluded that the increase in productivity came from the attention given to the workers by the management. It had increased their motivation and so they had worked harder. In other words, if you take an interest in others, they will want to please you and you will have good relations with them.
___73___. After Martin Luther King, Jr was killed in 1960s, a teacher, Jane Elliott, living in an all- white town decided to help her class of young children understand why the Civil Rights Movement had been necessary in America.
She divided the class into two groups: one with blue eyes and other with brown eyes. Other eye colors such as hazel or green were excluded from his exercise. Then she told the class that brown-eyed people were cleverer than blue-eyed ones because of an agent(化學(xué)作用) for brown color found in their blood. Blue-eyed people were stupid, lazy and not to be trusted. Jane Elliott did not need to say any more. The brown-eyed students quickly got used to their new role as the leaders of the class. The blue-eyed students became quiet and withdrawn. Then she discovered something very interesting. Four poor brown-eyed readers began to read fluently in a way they had never done before. ___74___. So if you want to be successful and happy, take an interest in others whether they are your classmates or workmates. Congratulate them on their success and sympathize with them in their troubles. ___75___.
A．Before the experiment the management talked to both groups of workers and explained that they wanted to find the best working environment for them.
B．Remember that the way you treat others will decide their attitude and behavior to you.
C．The second experiment shows what happens to personal relations if you are rude to or ignore others.
D．The ones who have more friends usually are those who care about others.
E. Jane Elliott had shown that the way people are treated affects not only their behavior but also their confidence and their performance.
F. You may even imagine that this ability was something they were born with because it seems so effortless to them.
G. The second experiment tells us what teachers said had a great effect on the students.

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科目：初中物理 來(lái)源：2012屆江蘇省通州市中考網(wǎng)閱適應(yīng)性測(cè)試物理試卷（帶解析） 題型：綜合題

閱讀短文，回答問(wèn)題：
如圖甲是一種可調(diào)溫蒸汽電熨斗，其說(shuō)明書(shū)的部分內(nèi)容如下：

產(chǎn)品特點(diǎn)：
具有干濕兩用功能．干用功能是指在無(wú)水狀態(tài)下，通過(guò)電加熱管加熱底板，底板溫度上升，直接壓燙衣物；濕用功能是指在蒸汽狀態(tài)下熨燙．
自動(dòng)恒溫設(shè)置．針對(duì)不同面料可調(diào)節(jié)底板溫度．
技術(shù)參數(shù)：
自身質(zhì)量：1.3kg  額定功率：1000W 額定電壓：220V  
在額定電壓下工作時(shí)能達(dá)到的最大噴氣量：15g/min 
（1）某師傅在用熨斗干燙衣服時(shí)，用了19N向下的力壓熨斗，如果熨斗底板與衣服接觸的面積為160 cm2，在此過(guò)程中，衣服受到的壓強(qiáng)為             Pa．(g取10 N/kg)
（2）用熨斗汽燙前先預(yù)熱，使金屬底板的溫度從20℃升高到220℃，溫控開(kāi)關(guān)自動(dòng)斷開(kāi)．已知金屬底板的質(zhì)量為1kg，金屬底板的比熱容為0.46×103J/（kg?℃）．則蒸汽電熨斗預(yù)熱過(guò)程中金屬底板吸收的熱量為           J．
（3）設(shè)計(jì)生產(chǎn)電熨斗時(shí)，技術(shù)人員會(huì)根據(jù)不同部分的作用選用具有不同物理屬性的材料．“水位觀察窗”選用的材料應(yīng)具有很好的         （選填“硬度”、“延展性”或“透明度”）；用熨斗汽燙時(shí)，可以看到熨斗底板蒸汽口的周?chē)写罅俊鞍嘴F”，這是因?yàn)樗?u>    后    （上兩格均填物態(tài)變化名稱(chēng)）形成的小水珠；某次使用時(shí)發(fā)現(xiàn)從蒸汽口噴出的是水柱而不是“白霧”，請(qǐng)你猜想可能的原因是          ．
（4）若某次使用中，該電熨斗(額定電壓下)在最大噴氣量狀態(tài)下工作時(shí)消耗的電能中只有70%被水吸收，則該狀態(tài)下每克水噴出前吸收的熱量是        J．

（5）如圖乙所示為自動(dòng)調(diào)溫電熨斗的電路圖．右下方為溫控部分，A為雙金屬片，由兩層不同金屬粘合而成，受熱時(shí)二者膨脹的快慢不同．在未通電和低于預(yù)定溫度時(shí)，雙金屬片A和靜片B上的觸點(diǎn)接通，指示燈L亮，電熱絲R發(fā)熱，當(dāng)溫度達(dá)到預(yù)定溫度時(shí)，由于雙金屬片的金屬層       （填“a”或“b”）膨脹較快，向左彎曲，電路斷開(kāi)，如圖丙所示．調(diào)節(jié)調(diào)溫旋鈕C，使靜片向左時(shí)，調(diào)溫電熨斗的預(yù)定溫度值將變______（選填“高”、“低”）．

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科目：初中物理 來(lái)源：2011-2012學(xué)年江蘇省通州市中考網(wǎng)閱適應(yīng)性測(cè)試物理試卷（解析版） 題型：綜合題

閱讀短文，回答問(wèn)題：

如圖甲是一種可調(diào)溫蒸汽電熨斗，其說(shuō)明書(shū)的部分內(nèi)容如下：

產(chǎn)品特點(diǎn)：

具有干濕兩用功能．干用功能是指在無(wú)水狀態(tài)下，通過(guò)電加熱管加熱底板，底板溫度上升，直接壓燙衣物；濕用功能是指在蒸汽狀態(tài)下熨燙．

自動(dòng)恒溫設(shè)置．針對(duì)不同面料可調(diào)節(jié)底板溫度．

技術(shù)參數(shù)：

自身質(zhì)量：1.3kg   額定功率：1000W  額定電壓：220V  

在額定電壓下工作時(shí)能達(dá)到的最大噴氣量：15g/min  

（1）某師傅在用熨斗干燙衣服時(shí)，用了19N向下的力壓熨斗，如果熨斗底板與衣服接觸的面積為160 cm2，在此過(guò)程中，衣服受到的壓強(qiáng)為             Pa．(g取10 N/kg)

（2）用熨斗汽燙前先預(yù)熱，使金屬底板的溫度從20℃升高到220℃，溫控開(kāi)關(guān)自動(dòng)斷開(kāi)．已知金屬底板的質(zhì)量為1kg，金屬底板的比熱容為0.46×103J/（kg•℃）．則蒸汽電熨斗預(yù)熱過(guò)程中金屬底板吸收的熱量為            J．

（3）設(shè)計(jì)生產(chǎn)電熨斗時(shí)，技術(shù)人員會(huì)根據(jù)不同部分的作用選用具有不同物理屬性的材料．“水位觀察窗”選用的材料應(yīng)具有很好的          （選填“硬度”、“延展性”或“透明度”）；用熨斗汽燙時(shí)，可以看到熨斗底板蒸汽口的周?chē)写罅俊鞍嘴F”，這是因?yàn)樗?u>     后     （上兩格均填物態(tài)變化名稱(chēng)）形成的小水珠；某次使用時(shí)發(fā)現(xiàn)從蒸汽口噴出的是水柱而不是“白霧”，請(qǐng)你猜想可能的原因是           ．

（4）若某次使用中，該電熨斗(額定電壓下)在最大噴氣量狀態(tài)下工作時(shí)消耗的電能中只有70%被水吸收，則該狀態(tài)下每克水噴出前吸收的熱量是         J．

（5）如圖乙所示為自動(dòng)調(diào)溫電熨斗的電路圖．右下方為溫控部分，A為雙金屬片，由兩層不同金屬粘合而成，受熱時(shí)二者膨脹的快慢不同．在未通電和低于預(yù)定溫度時(shí)，雙金屬片A和靜片B上的觸點(diǎn)接通，指示燈L亮，電熱絲R發(fā)熱，當(dāng)溫度達(dá)到預(yù)定溫度時(shí)，由于雙金屬片的金屬層        （填“a”或“b”）膨脹較快，向左彎曲，電路斷開(kāi)，如圖丙所示．調(diào)節(jié)調(diào)溫旋鈕C，使靜片向左時(shí)，調(diào)溫電熨斗的預(yù)定溫度值將變___ ___（選填“高”、“低”）．

 

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