分析:(1)原式變?yōu)?.3x=9.2,根據(jù)等式的性質(zhì),兩邊同除以2.3即可;
(2)原式變?yōu)?.5x=75,根據(jù)等式的性質(zhì),兩邊同除以7.5即可;
(3)原式變?yōu)?8-0.2x=28,根據(jù)等式的性質(zhì),兩邊同加上0.2x,得28+0.2x=48,兩邊同減去28,再同除以0.2即可.
解答:解:(1)2x+30%x=9.2
2x+0.3x=9.2
2.3x=9.2
2.3x÷2.3=9.2÷2.3
x=4
(2)7x+50%x=75
7x+0.5x=75
7.5x=75
7.5x÷7.5=75÷7.5
x=10
(3)48-20%x=28
48-0.2x=28
48-0.2x+0.2x=28+0.2x
28+0.2x=48
28+0.2x-28=48-28
0.2x=20
0.2x÷0.2=20÷0.2
x=100
點評:此題考查了根據(jù)等式的性質(zhì)解方程,即等式兩邊同加上、同減去、同乘上或同除以一個不為0的數(shù),等式仍相等.同時注意“=”上下要對齊.